Find the derivative of d{(1/√x)+xln(x^3)}/dx

 Steps to solve Find the derivative of d{(1/√x)+xln(x^3)}/dx

=d{(1/√x)+xln(x^3)}/dx

=d(1/√x)/dx+d{xln(x^3)}/dx

=dx^(-1/2)/dx+d(3xlnx)/dx

=(-1/2)x^(-3/2)+3[x{dlnx/dx}+lnx(dx/dx)]

=(-1/2)x^(-3/2)+3{(x/3)+1}

Hence the derivative of (1/√x)+xln(x^3) is (-1/2)x^(-3/2)+3{(x/3)+1}

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