Find the value of 2.sin67(1/2).cos22(1/2)
September 25, 2021
Steps to solve Find the value of 2.sin67(1/2).cos22(1/2)
=2.sin67(1/2).cos22(1/2)
=2.sin(135/2).cos(45/2)
=sin{(135/2)+(45/2)}+sin{(135/2)-(45/2)}
=sin(180/2)+sin(90/2)
=1+(1/√2)
=(√2+1)/√2
Hence the value of 2.sin67(1/2).cos22(1/2) is (√2+1)/√2
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