Find the derivative of d(tan2x+sec2x)/dx

Steps to solve Find the derivative of d(tan2x+sec2x)/dx

=d(tan2x+sec2x)/dx

=dtan2x/dx+dsec2x/dx

=sec^2(2x).2+sec2x.tan2x.2

=2sec^2(2x)+2sec2xtan2x

Hence the derivative of tan2x+sec2x is 2sec^2(2x)+2sec2xtan2x

Detail Information:-

Similar Questions For You:-

• Find the derivative of d{x^2-x+2}^2/dx
• Find the derivative of d{x^2+2x-sinx+5}/dx
• Find the derivative of d{(1/2)x^(1/2)+(1/3)x^(1/3)}/dx
• Find the derivative of d{√x(√x+1)}/dx