Find the derivative of d{x^2+2x-sinx+5}/dx
October 06, 2021
Steps to solve the derivative of d{x^2+2x-sinx+5}/dx
=d{x^2+2x-sinx+5}/dx
=d(x^2)/dx+d2x/dx-d(sinx+5)/dx
=2x+2-cosx+0
=2x+2-cosx
Hence the derivative of d{x^2+2x-sinx+5}/dx is 2x+2-cosx
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