Find the derivative of d{ax^2+btanx+ln(x^3)}/dx

 Steps to solve the derivative of d{ax^2+btanx+ln(x^3)}/dx

=d{ax^2+btanx+ln(x^3)}/dx

=d(ax^2)/dx+d(btanx)/dx+d{ln(x^3)}/dx

=a2x+bsec^2x+(1/x^3)3x^2

=2ax+bsec^2x+3x^2/x^3

=2ax+bsec^2x+3/x

Hence the derivative of d{ax^2+btanx+ln(x^3)}/dx is 2ax+bsec^2x+3/x

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