Find the general value of sin(x+40)=1/√2

 Steps to solve find the general value of sin(x+40)=1/√2

⇒sin(x+40)=sinπ/4

⇒x+40=nπ+(-1)^n(π/4)

⇒x=nπ+(-1)^n(π/4)-40

⇒πx/180=nπ+(-1)^n(π/4)-40

⇒x=180nπ/π+(-1)^n(π/4)(180/π)-40(180/π)

⇒x=180n+(-1)^n45-40

Hence the general value of sin(x+40)=1/rt2 is 180n+(-1)^n45-40

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