Find the general solution for sin(x+40)=1/√2

Steps to solve Find the general solution for sin(x+40)=1/√2

⇒sin(x+40)=1/√2

⇒sin(x+40)=sinπ/4

⇒x=nπ+(-1)^n(π/4)-40

⇒πx/180=nπ+(-1)^n(π/4)-40

⇒x=(180/π){nπ+(-1)^n(π/4)-40}

⇒x=(180/π)nπ+(180/π)(-1)^n(π/4)-40(180/π)

⇒x=180n+(-1)^n(180/π)-1.40

⇒x=180n+(-1)^n.45-40

Hence the general solution for sin(x+40)=1/√2 is 180n+(-1)^n.45-40

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